Projectile Motion Study Pack

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Last updated May 27, 2026

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Projectile Motion Study Guide

Break down projectile motion by analyzing horizontal and vertical components independently, using kinematic equations to track velocity, range, and time of flight.

Key Takeaways

  • Projectile motion combines a constant horizontal velocity with a vertically accelerating component, and these two dimensions are analyzed independently using separate kinematic equations.
  • The only force acting on a projectile (ignoring air resistance) is gravity, which produces a constant downward acceleration of 9.8 m/s² and has no effect on horizontal motion.
  • The initial velocity vector is resolved into horizontal (v₀cosθ) and vertical (v₀sinθ) components using trigonometry, and each component is tracked separately throughout the flight.
  • A projectile launched and landing at the same height reaches maximum range at a launch angle of 45°, and complementary angles (e.g., 30° and 60°) produce equal horizontal ranges.
  • At the peak of a projectile's trajectory, the vertical velocity equals zero while the horizontal velocity remains unchanged, making the total speed at that instant equal solely to the horizontal component.
  • Time of flight is determined entirely by the vertical motion equations, and that same time value is then used to calculate horizontal displacement.

The Core Principle: Independence of Motion Components

Projectile motion rests on a single foundational idea — horizontal and vertical motion are completely independent of each other and can be analyzed using separate sets of equations applied to the same time interval.

Why the Two Dimensions Do Not Interfere

  • Gravity acts exclusively in the vertical direction, so it accelerates the object downward at 9.8 m/s² without altering the object's horizontal velocity at any point.
  • A ball rolled off a table and a ball dropped straight down from the same height hit the ground at the same moment, demonstrating that horizontal motion does not influence the rate of vertical fall.
  • This independence means you can solve for time using vertical equations and then use that time value in horizontal equations — the two sets share only the time variable.

What Qualifies as a Projectile

  • An object is treated as a projectile once it has been launched and is moving freely under gravity alone, with no engine, thrust, or propulsion force acting on it.
  • Air resistance is neglected in standard introductory analysis, which allows gravity to be the sole acceleration in the system.
  • Common examples include a thrown ball, a kicked soccer ball, a bullet fired horizontally, and water leaving the end of a horizontal pipe.

Decomposing the Initial Velocity Vector

When a projectile is launched at an angle, the initial velocity must be broken into its horizontal and vertical parts before any equations can be applied — this process is called vector decomposition.

Using Trigonometry to Find Components

  • If the initial speed is v₀ and the launch angle above the horizontal is θ, the horizontal component is v₀x = v₀cosθ and the vertical component is v₀y = v₀sinθ.
  • At θ = 0° (purely horizontal launch), all of the initial velocity is horizontal and v₀y = 0, meaning the object begins falling immediately with no initial upward motion.
  • At θ = 90° (straight up), all of the initial velocity is vertical and the projectile rises and falls along a single vertical line with no horizontal displacement.

How Component Magnitudes Change During Flight

  • The horizontal component v₀x remains constant throughout the entire flight because no horizontal force acts on the projectile.
  • The vertical component changes continuously: it decreases at 9.8 m/s² on the way up, reaches zero at the peak, then increases in the downward direction on the way down.
  • Reconstructing the actual velocity at any moment requires combining both components using the Pythagorean theorem: v = √(vx² + vy²), and the direction is found using the inverse tangent of vy/vx.

Kinematic Equations Applied to Each Axis

The standard one-dimensional kinematic equations are applied separately to the horizontal and vertical axes, with the key difference being that vertical motion involves acceleration while horizontal motion does not.

Vertical Axis Equations

  • Because gravity provides a constant downward acceleration (g = 9.8 m/s²), the vertical position at time t is given by: y = v₀y·t − ½g·t².
  • The vertical velocity at any time t is: vy = v₀y − g·t, which equals zero at the moment of maximum height.
  • Maximum height H is reached when vy = 0, giving H = v₀y²/(2g) for a projectile launched from ground level.

Horizontal Axis Equations

  • Because no horizontal acceleration exists, horizontal position simplifies to: x = v₀x·t.
  • The horizontal velocity vx = v₀cosθ is constant — it appears in no acceleration term and does not change regardless of where in the trajectory the object is.
  • Horizontal range R for a projectile that lands at the same height from which it was launched is: R = v₀²sin(2θ)/g, derived by substituting the full time of flight into x = v₀x·t.

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Projectile Motion Study Pack | Kibin